Velocity & Acceleration in SHM question from NEET 2017

Answer: (b)

1. $\omega\sqrt{A^2 - x^2} = \omega^2 x$ with $A = 3$, $x = 2$.
2. $\sqrt{9 - 4} = 2\omega \Rightarrow \omega = \frac{\sqrt{5}}{2}$ rad/s.
3. $T = \frac{2\pi}{\omega} = \frac{4\pi}{\sqrt{5}}$ s.
4. So the answer is (b) $\frac{4\pi}{\sqrt{5}}$.