Physics Circle home Student Login

Home›Chapters›Oscillations PYQs›Velocity & Acceleration in SHM›Question 56

JEE Main 2021 (26 Feb, Shift 2) · Velocity & Acceleration in SHM

Velocity & Acceleration in SHM question from JEE Main 2021 (26 Feb, Shift 2)

Q56JEE Main 2021 · 26 FEB · SHIFT 2Easy

Velocity & Acceleration in SHM

A particle executes S.H.M., the graph of velocity as a function of displacement is:

Show answer and solution

Answer: (c)

  1. v2=ω2(A2−x2)⇒x2A2+v2ω2A2=1v^2 = \omega^2(A^2 - x^2) \Rightarrow \frac{x^2}{A^2} + \frac{v^2}{\omega^2A^2} = 1.
  2. This is the equation of an ellipse (a circle only in the special case ω=1\omega = 1).
  3. So the answer is (c) an ellipse.
Report a mistake

More questions on Velocity & Acceleration in SHM