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JEE Main 2023 (13 Apr, Shift 2) · Energy in SHM

Energy in SHM question from JEE Main 2023 (13 Apr, Shift 2)

Q38JEE Main 2023 · 13 APR · SHIFT 2Easy

Energy in SHM

A particle executes SHM of amplitude A. The distance from the mean position when its kinetic energy becomes equal to its potential energy is:

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Answer: (a)

  1. KE=PE⇒PE=E2KE = PE \Rightarrow PE = \frac{E}{2}.
  2. 12kx2=12⋅12kA2⇒x2=A22\frac{1}{2}kx^2 = \frac{1}{2}\cdot\frac{1}{2}kA^2 \Rightarrow x^2 = \frac{A^2}{2}
  3. x=A2x = \frac{A}{\sqrt{2}}
  4. So the answer is (a) 12A\frac{1}{\sqrt{2}}A.
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