A particle executes simple harmonic motion between x = -A and x = +A. If time taken by particle to go from x = 0 to A/2 is 2 s; then time taken by particle in going from x = A/2 to A is (a) 4 s (b) 1.5 s (c) 3 s (d) 2 s

Answer: (a). 0 → A/2 takes T/12 = 2 s ⇒ T = 24 s A/2 → A takes T/4 - T/12 = T/6 = 4 s So the answer is (a) 4 s.

A particle executes simple harmonic motion between x = -A and x = +A… | JEE Main 2023 (25 Jan, Shift 2)

Q37JEE Main 2023 · 25 JAN · SHIFT 2Medium

Periodic Motion & SHM Basics

A particle executes simple harmonic motion between $x = -A$ and $x = +A$ . If time taken by particle to go from $x = 0$ to $\frac{A}{2}$ is 2 s; then time taken by particle in going from $x = \frac{A}{2}$ to A is

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Answer: (a)

$0 \to \frac{A}{2}$ takes $\frac{T}{12} = 2\text{ s} \Rightarrow T = 24\text{ s}$
$\frac{A}{2} \to A$ takes $\frac{T}{4} - \frac{T}{12} = \frac{T}{6} = 4\text{ s}$
So the answer is (a) 4 s.

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