A particle executes simple harmonic motion between x = -A and x = +A. If time taken by particle to go from x = 0 to A/2 is 2 s, then time taken by particle in going from x = A/2 to A is (a) 3 s (b) 2 s (c) 1.5 s (d) 4 s

Answer: (d). From x = 0 to A/2: phase π/6, time T/12 = 2 s ⇒ T = 24 s From A/2 to A: phase π/2 - π/6 = π/3, time T/6 = 4 s So the answer is (d) 4 s.

A particle executes simple harmonic motion between x = -A and x = +A… | MHT CET 2026 (11 Apr, Shift 1)

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Periodic Motion & SHM Basics

A particle executes simple harmonic motion between $x = -A$ and $x = +A$ . If time taken by particle to go from $x = 0$ to $\frac{A}{2}$ is $2$ s, then time taken by particle in going from $x = \frac{A}{2}$ to A is

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Answer: (d)

From $x = 0$ to $\frac{A}{2}$ : phase $\frac{\pi}{6}$ , time $\frac{T}{12} = 2\text{ s} \Rightarrow T = 24\text{ s}$
From $\frac{A}{2}$ to $A$ : phase $\frac{\pi}{2} - \frac{\pi}{6} = \frac{\pi}{3}$ , time $\frac{T}{6} = 4\text{ s}$
So the answer is (d) 4 s.

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