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MHT CET 2019 (2 May, Shift 1) · Periodic Motion & SHM Basics

Periodic Motion & SHM Basics question from MHT CET 2019 (2 May, Shift 1)

Q59MHT CET 2019 · 2 MAY · SHIFT 1Easy

Periodic Motion & SHM Basics

A particle executes the simple harmonic motion with an amplitude ' $A$ '. The distance travelled by it in one periodic time is

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Answer: (d)

In one period the particle goes mean $\to$ $+A$ $\to$ mean $\to$ $-A$ $\to$ mean.
Distance $= A + A + A + A = 4A$ .
So the answer is (d) $4A$ .

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