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NEET 2005 (AIPMT) · Velocity & Acceleration in SHM

Velocity & Acceleration in SHM question from NEET 2005 (AIPMT)

Q83NEET 2005 · AIPMTEasy

Velocity & Acceleration in SHM

A particle executing simple harmonic motion of amplitude 5 cm5\text{ cm} has maximum speed of 31.4 cm/s31.4\text{ cm/s}. The frequency of its oscillation is

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Answer: (d)

  1. vmax=Aω⇒ω=31.45=6.28v_{max} = A\omega \Rightarrow \omega = \frac{31.4}{5} = 6.28 rad/s
  2. f=ω2π=6.286.28=1f = \frac{\omega}{2\pi} = \frac{6.28}{6.28} = 1 Hz
  3. So the answer is (d) 1 Hz.
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