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JEE Main 2009 (AIEEE) · Motion in a Plane (2-D Kinematics)

Motion in a Plane (2-D Kinematics) question from JEE Main 2009 (AIEEE)

Q23JEE Main 2009 · AIEEEEasy

Motion in a Plane (2-D Kinematics)

A particle has an initial velocity 3i^+4j^3\hat{i} + 4\hat{j} and an acceleration of 0.4i^+0.3j^0.4\hat{i} + 0.3\hat{j}. Its speed after 10 s is:

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Answer: (a)

  1. v⃗=u⃗+a⃗t=(3+0.4×10)i^+(4+0.3×10)j^=7i^+7j^\vec v = \vec u + \vec a t = (3 + 0.4\times10)\hat i + (4 + 0.3\times10)\hat j = 7\hat i + 7\hat j
  2. Speed =49+49=72= \sqrt{49 + 49} = 7\sqrt2 units
  3. So the answer is (a) 727\sqrt2 units.
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