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NEET 2015 (AIPMT) · Velocity & Acceleration in SHM

Velocity & Acceleration in SHM question from NEET 2015 (AIPMT)

Q71NEET 2015 · AIPMTEasy

Velocity & Acceleration in SHM

A particle is executing a simple harmonic motion. Its maximum acceleration is α\alpha and maximum velocity is β\beta. Then, its time period of vibration will be

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Answer: (b)

  1. α=Aω2\alpha = A\omega^2, β=Aω\beta = A\omega
  2. ω=αβ\omega = \frac{\alpha}{\beta}
  3. T=2πω=2πβαT = \frac{2\pi}{\omega} = \frac{2\pi\beta}{\alpha}
  4. So the answer is (b) 2πβα\frac{2\pi\beta}{\alpha}.
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