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JEE Main 2019 (9 Jan, Shift 2) · Energy in SHM

Energy in SHM question from JEE Main 2019 (9 Jan, Shift 2)

Q68JEE Main 2019 · 9 JAN · SHIFT 2Easy

Energy in SHM

A particle is executing simple harmonic motion (SHM) of amplitude A, along the x-axis, about x = 0. When its potential Energy (PE) equals kinetic energy (KE), the position of the particle will be:

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Answer: (c)

$PE = KE \Rightarrow kx^2 = \frac{1}{2}kA^2$
$x = \frac{A}{\sqrt{2}}$ (on either side of $x = 0$ )
So the answer is (c) $\frac{A}{\sqrt{2}}$ .

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