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Energy in SHM question from JEE Main 2017

Q70JEE Main 2017Easy

Energy in SHM

A particle is executing simple harmonic motion with a time period T. At time t = 0, it is at its position of equilibrium. The kinetic energy – time graph of the particle will look like:

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Answer: (a)

At $t = 0$ the particle is at equilibrium: $x = A\sin\omega t$ , $KE = E\cos^2\omega t$ .
KE is maximum at $t = 0$ , zero at $t = T/4$ , maximum again at $T/2$ .
KE repeats every $T/2$ and is never negative.
So the answer is (a).

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