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JEE Main 2020 (2 Sep, Shift 2) · Matter Waves: de Broglie Wavelength

Matter Waves: de Broglie Wavelength question from JEE Main 2020 (2 Sep, Shift 2)

Q114JEE Main 2020 · 2 SEP · SHIFT 2Medium

Matter Waves: de Broglie Wavelength

A particle is moving 5 times as fast as an electron. The ratio of the de-Broglie wavelength of the particle to that of the electron is 1.878 ×\times 10–4. The mass of the particle is close to

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Answer: (d)

  1. λλe=mevemv=me5m\dfrac{\lambda}{\lambda_e} = \dfrac{m_e v_e}{m v} = \dfrac{m_e}{5m} (since v=5vev = 5v_e).
  2. m=me5×1.878×10−4=9.1×10−319.39×10−4m = \dfrac{m_e}{5 \times 1.878 \times 10^{-4}} = \dfrac{9.1 \times 10^{-31}}{9.39 \times 10^{-4}}
  3. m≈9.7×10−28 kgm \approx 9.7 \times 10^{-28}\text{ kg}, so the answer is (d).
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