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JEE Main 2019 (11 Jan, Shift 1) · Angular Variables

Angular Variables question from JEE Main 2019 (11 Jan, Shift 1)

Q34JEE Main 2019 · 11 JAN · SHIFT 1Easy

Angular Variables

A particle is moving along a circular path with a constant speed of 10 ms–1. What is the magnitude of the change in velocity of the particle, when it moves through an angle of 60o around the centre of the circle?

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Answer: (b)

60°v₁ = 10v₂ = 10Δv = 10
  1. Speed is constant, only direction changes by θ=60∘\theta = 60^\circ.
  2. ∣Δv⃗∣=2vsin⁡θ2=2×10×sin⁡30∘|\Delta \vec v| = 2v\sin\frac{\theta}{2} = 2 \times 10 \times \sin 30^\circ.
  3. ∣Δv⃗∣=10|\Delta \vec v| = 10 m/s (the vector triangle is equilateral).
  4. So the answer is (b) 10 m/s.
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