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MHT CET 2021 (24 Sep, Shift 2) · Centripetal Acceleration & Force

Centripetal Acceleration & Force question from MHT CET 2021 (24 Sep, Shift 2)

Q31MHT CET 2021 · 24 SEP · SHIFT 2Easy

Centripetal Acceleration & Force

A particle is moving along the circular path with constant speed and centripetal acceleration 'a'. If the speed is doubled, the ratio of its acceleration after and before the change is

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Answer: (d)

$a = \frac{v^2}{r} \Rightarrow a \propto v^2$ for the same radius.
Doubling $v$ gives $a' = 4a$ .
So the answer is (d) $4:1$ .

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