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JEE Main 2005 (AIEEE) · Motion in a Plane (2-D Kinematics)

Motion in a Plane (2-D Kinematics) question from JEE Main 2005 (AIEEE)

Q25JEE Main 2005 · AIEEEEasy

Motion in a Plane (2-D Kinematics)

A particle is moving eastwards with a velocity of 5 m/s. In 10 seconds the velocity changes to 5 m/s northwards. The average acceleration in this time is

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Answer: (c)

  1. Δv⃗=v⃗2−v⃗1=5 N^−5 E^=5 N^+5 W^\Delta\vec v = \vec v_2 - \vec v_1 = 5\,\hat N - 5\,\hat E = 5\,\hat N + 5\,\hat W
  2. ∣Δv⃗∣=52|\Delta\vec v| = 5\sqrt2 m/s, directed north-west
  3. aav=5210=12a_{av} = \frac{5\sqrt2}{10} = \frac{1}{\sqrt2} m s−2^{-2}
  4. So the answer is (c) 12\frac{1}{\sqrt2} m s−2^{-2} towards north-west.
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