A particle is moving in a circle with uniform speed ' v '. In moving from a point to another diametrically opposite point (a) the momentum changes by mv (b) the momentum changes by 2mv (c) the kinetic energy changes by 1/2mv² (d) the kinetic energy changes by mv²

Answer: (b). At the diametrically opposite point the velocity is reversed: v → - v. |Δ p| = mv - (-mv) = 2mv. Speed is unchanged, so kinetic energy does not change. So the answer is (b) the momentum changes by 2mv.

A particle is moving in a circle with uniform speed ' v '. In moving… | MHT CET 2023 (12 May, Shift 2)

Q25MHT CET 2023 · 12 MAY · SHIFT 2Medium

Angular Variables

A particle is moving in a circle with uniform speed ' $v$ '. In moving from a point to another diametrically opposite point

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Answer: (b)

At the diametrically opposite point the velocity is reversed: $\vec v \to -\vec v$ .
$|\Delta \vec p| = mv - (-mv) = 2mv$ .
Speed is unchanged, so kinetic energy does not change.
So the answer is (b) the momentum changes by $2mv$ .

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Angular Variables question from MHT CET 2023 (12 May, Shift 2)

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