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MHT CET 2026 (16 Apr, Shift 1) · Non-Uniform Circular Motion

Non-Uniform Circular Motion question from MHT CET 2026 (16 Apr, Shift 1)

Q4MHT CET 2026 · 16 APR · SHIFT 1Medium

Non-Uniform Circular Motion

A particle is moving with constant angular acceleration 44 rad/s2^{2} in circular path. At what time the magnitudes of its tangential acceleration and centripetal acceleration will be equal?

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Answer: (c)

  1. Starting from rest: ω=αt\omega = \alpha t
  2. at=rαa_t = r\alpha, ac=ω2r=α2t2ra_c = \omega^2 r = \alpha^2 t^2 r
  3. Equal: α2t2r=rα⇒t=1α=14\alpha^2 t^2 r = r\alpha \Rightarrow t = \frac{1}{\sqrt{\alpha}} = \frac{1}{\sqrt{4}}
  4. So the answer is (c) 0.50.5 s.
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