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MHT CET 2025 (26 Apr, Shift 2) · Velocity & Acceleration in SHM

Velocity & Acceleration in SHM question from MHT CET 2025 (26 Apr, Shift 2)

Q17MHT CET 2025 · 26 APR · SHIFT 2Easy

Velocity & Acceleration in SHM

A particle is performing S.H.M. starting from extreme position. Graphical representation shows that between displacement and acceleration, there is a phase difference of

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Answer: (a)

In SHM $a = -\omega^2 x$ : acceleration is always opposite to displacement.
$-\cos\theta = \cos(\theta + \pi)$ , so the acceleration graph is the displacement graph shifted by $\pi$ .
So the answer is (a) $\pi$ rad.

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