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MHT CET 2021 (21 Sep, Shift 2) · Velocity & Acceleration in SHM

Velocity & Acceleration in SHM question from MHT CET 2021 (21 Sep, Shift 2)

Q54MHT CET 2021 · 21 SEP · SHIFT 2Easy

Velocity & Acceleration in SHM

A particle is performing S.H.M. with maximum velocity 'vv'. If the amplitude is tripled and periodic time is doubled then maximum velocity will be

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Answer: (a)

  1. vmax=2πATv_{max} = \frac{2\pi A}{T}, so vmax∝ATv_{max} \propto \frac{A}{T}
  2. A′=3AA' = 3A, T′=2TT' = 2T: v′=32v=1.5vv' = \frac{3}{2}v = 1.5v
  3. So the answer is (a) 1.5v1.5v.
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