A particle is performing U.C.M. along the circumference of a circle of diameter 50 cm with frequency 2 Hz. The acceleration of the particle in m/s² is (a) 2π² (b) 4π² (c) 8π² (d) π²

Answer: (b). r = 25 cm = 0.25 m, ω = 2π n = 4π rad/s. a = ω² r = 16π² × 0.25 = 4π² m/s ². So the answer is (b) 4π².

A particle is performing U.C.M. along the circumference of a circle… | MHT CET 2021 (23 Sep, Shift 2)

Q32MHT CET 2021 · 23 SEP · SHIFT 2Easy

Centripetal Acceleration & Force

A particle is performing U.C.M. along the circumference of a circle of diameter $50\text{ cm}$ with frequency $2\text{ Hz}$ . The acceleration of the particle in $\text{m/s}^2$ is

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Answer: (b)

$r = 25$ cm $= 0.25$ m, $\omega = 2\pi n = 4\pi$ rad/s.
$a = \omega^2 r = 16\pi^2 \times 0.25 = 4\pi^2$ m/s $^2$ .
So the answer is (b) $4\pi^2$ .

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