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JEE Main 2007 (AIEEE) · Conservation of Energy

Conservation of Energy question from JEE Main 2007 (AIEEE)

Q35JEE Main 2007 · AIEEEEasy

Conservation of Energy

A particle is projected at $60^\circ$ to the horizontal with a kinetic energy K. The kinetic energy at the highest point is

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Answer: (d)

At the highest point the speed is $u\cos\theta$ , so $K_{top} = K\cos^2\theta$ .
$K_{top} = K\cos^2 60^\circ = \frac{K}{4}$
So the answer is (d) $K/4$ .

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