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NEET 2001 (AIPMT) · Conservation of Energy

Conservation of Energy question from NEET 2001 (AIPMT)

Q42NEET 2001 · AIPMTEasy

Conservation of Energy

A particle is projected making an angle of 45° with horizontal having kinetic energy K. The kinetic energy at highest point will be

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Answer: (b)

  1. At the top, speed =vcos⁡45∘= v\cos 45^\circ, so KE=Kcos⁡245∘KE = K\cos^2 45^\circ.
  2. KE=K×12KE = K \times \frac{1}{2}
  3. So the answer is (b) K2\frac{K}{2}.
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