A particle is suspended from a vertical spring which is executing S.H.M. of frequency 5 Hz. The spring is unstretched at the highest point of oscillation. Maximum speed of the particle is (g = 10 m/s²) (a) 1/π m/s (b) 1/4π m/s (c) 1/2π m/s (d) π m/s

Answer: (a). Spring unstretched at the top, so A = (g)/(ω²) and vmax = (g)/(ω). ω = 2π f = 10π rad/s vmax = (10)/(10π) = 1/π m/s So the answer is (a).

A particle is suspended from a vertical spring which is executing… | MHT CET 2021 (20 Sep, Shift 2)

Q70MHT CET 2021 · 20 SEP · SHIFT 2Medium

Spring Systems

A particle is suspended from a vertical spring which is executing S.H.M. of frequency $5\text{ Hz}$ . The spring is unstretched at the highest point of oscillation. Maximum speed of the particle is $(g = 10\text{ m/s}^2)$

Show answer and solution

Answer: (a)

Spring unstretched at the top, so $A = \frac{g}{\omega^2}$ and $v_{max} = \frac{g}{\omega}$ .
$\omega = 2\pi f = 10\pi$ rad/s
$v_{max} = \frac{10}{10\pi} = \frac{1}{\pi}$ m/s
So the answer is (a).

Report a mistake

Spring Systems question from MHT CET 2021 (20 Sep, Shift 2)

More questions on Spring Systems