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NEET 2001 (AIPMT) · Motion Under Gravity

Motion Under Gravity question from NEET 2001 (AIPMT)

Q59NEET 2001 · AIPMTEasy

Motion Under Gravity

A particle is thrown vertically upward. Its velocity at half of the height is 10 m/s, then the maximum height attained by it (g = 10 m/s2)

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Answer: (c)

  1. Maximum height: u2=2gHu^2 = 2gH; at H/2H/2: v2=u2−gH=gHv^2 = u^2 - gH = gH
  2. 102=10×H⇒H=1010^2 = 10 \times H \Rightarrow H = 10 m
  3. So the answer is (c) 10 m.
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