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MHT CET 2023 (9 May, Shift 2) · Energy in SHM

Energy in SHM question from MHT CET 2023 (9 May, Shift 2)

Q37MHT CET 2023 · 9 MAY · SHIFT 2Easy

Energy in SHM

A particle is vibrating in S.H.M. with an amplitude of 4 cm4\text{ cm}. At what displacement from the equilibrium position is its energy half potential and half kinetic?

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Answer: (d)

  1. KE=PE⇒A2−x2=x2KE = PE \Rightarrow A^2 - x^2 = x^2
  2. x=A2=42=22 cmx = \dfrac{A}{\sqrt{2}} = \dfrac{4}{\sqrt{2}} = 2\sqrt{2}\text{ cm}
  3. So the answer is (d) 222\sqrt{2} cm.
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