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NEET 2010 (AIPMT, Prelims) · Velocity, Acceleration & Variable Motion

Velocity, Acceleration & Variable Motion question from NEET 2010 (AIPMT, Prelims)

Q38NEET 2010 · AIPMT · PRELIMSMedium

Velocity, Acceleration & Variable Motion

A particle moves a distance x in time t according to equation x = (t + 5)−1{}^{-1}. The acceleration of particle is proportional to

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Answer: (a)

  1. x=(t+5)−1x = (t + 5)^{-1}, v=−(t+5)−2v = -(t + 5)^{-2}, a=2(t+5)−3a = 2(t + 5)^{-3}
  2. ∣v∣3/2=(t+5)−3|v|^{3/2} = (t + 5)^{-3}
  3. So a∝v3/2a \propto v^{3/2}; the answer is (a).
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