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MHT CET 2023 (11 May, Shift 1) · Rotational Kinematics & Dynamics

Rotational Kinematics & Dynamics question from MHT CET 2023 (11 May, Shift 1)

Q25MHT CET 2023 · 11 MAY · SHIFT 1Easy

Rotational Kinematics & Dynamics

A particle moves along a circular path with decreasing speed. Hence

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Answer: (c)

  1. Speed decreases, so there is a tangential acceleration too; the resultant acceleration is not towards the centre.
  2. The path is still the given circle, not a spiral.
  3. L=mvrL = mvr decreases in magnitude, but L⃗\vec{L} always points perpendicular to the plane of the circle.
  4. So the answer is (c): the direction of angular momentum stays constant.
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