A particle moves along a straight line such that its displacement at any time t is given by s = (t³ - 6t² + 3t + 4) metres. The velocity when the acceleration is zero is (a) 3 m/s (b) 42 m/s (c) -9 m/s (d) -15 m/s

Answer: (c). v = 3t² - 12t + 3, a = 6t - 12. a = 0 ⇒ t = 2 s. v = 3(4) - 24 + 3 = -9 m/s So the answer is (c) -9 m/s.

A particle moves along a straight line such that its displacement at… | NEET 1994 (AIPMT)

Q50NEET 1994 · AIPMTEasy

Velocity, Acceleration & Variable Motion

A particle moves along a straight line such that its displacement at any time $t$ is given by $s = (t^3 - 6t^2 + 3t + 4)$ metres. The velocity when the acceleration is zero is

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Answer: (c)

$v = 3t^2 - 12t + 3$ , $a = 6t - 12$ .
$a = 0 \Rightarrow t = 2$ s.
$v = 3(4) - 24 + 3 = -9$ m/s
So the answer is (c) $-9$ m/s.

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Velocity, Acceleration & Variable Motion question from NEET 1994 (AIPMT)

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