A particle moves from position 3i + 2j - 6k to 14i + 13j + 9k due to uniform force of (4i + j + 3k) N. If displacement is in metre then work done will be (a) 100 J (b) 200 J (c) 300 J (d) 250 J

Answer: (a). Work by a constant force: W = F. s = (14-3)i + (13-2)j + (9+6)k = 11i + 11j + 15k m W = 4(11) + 1(11) + 3(15) = 44 + 11 + 45 = 100 J So the answer is (a) 100 J.

A particle moves from position 3i + 2j - 6k to 14i + 13j + 9k due to… | MHT CET 2026 (13 May, Shift 1)

Q1MHT CET 2026 · 13 MAY · SHIFT 1Easy

Work by a Constant Force

A particle moves from position $3\hat{i} + 2\hat{j} - 6\hat{k}$ to $14\hat{i} + 13\hat{j} + 9\hat{k}$ due to uniform force of $(4\hat{i} + \hat{j} + 3\hat{k})$ N. If displacement is in metre then work done will be

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Answer: (a)

Work by a constant force: $W = \vec{F}\cdot\vec{s}$ .
$\vec{s} = (14-3)\hat{i} + (13-2)\hat{j} + (9+6)\hat{k} = 11\hat{i} + 11\hat{j} + 15\hat{k}$ m
$W = 4(11) + 1(11) + 3(15) = 44 + 11 + 45 = 100$ J
So the answer is (a) $100$ J.

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