A particle moves in a straight line with a constant acceleration. It changes its velocity from 10 ms ⁻¹ to 20 ms ⁻¹ while passing through a distance 135 m in t second. The value of t is (a) 12 (b) 9 (c) 10 (d) 1.8

Answer: (b). For uniform acceleration s = (u + v)/(2) t. 135 = (10 + 20)/(2) t = 15t t = 9 s. So the answer is (b).

A particle moves in a straight line with a constant acceleration. It… | NEET 2008 (AIPMT)

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Equations of Kinematics

A particle moves in a straight line with a constant acceleration. It changes its velocity from 10 ms ${}^{-1}$ to 20 ms ${}^{-1}$ while passing through a distance 135 m in t second. The value of t is

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Answer: (b)

For uniform acceleration $s = \frac{u + v}{2}\,t$ .
$135 = \frac{10 + 20}{2}\,t = 15t$
$t = 9\text{ s}$ . So the answer is (b).

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