A particle moves with a velocity (5i - 3j + 6k) m s⁻¹ horizontally under the action of constant force (10i + 10j + 20k) N. The instantaneous power supplied to the particle is: (a) 200 W (b) Zero (c) 100 W (d) 140 W

Answer: (d). P = F · v. P = (10)(5) + (10)(-3) + (20)(6) = 50 - 30 + 120 = 140 W So the answer is (d) 140 W.

A particle moves with a velocity (5i - 3j + 6k) m s⁻¹ horizontally… | NEET 2023

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Power

A particle moves with a velocity $(5\hat{i} - 3\hat{j} + 6\hat{k})\text{ m s}^{-1}$ horizontally under the action of constant force $(10\hat{i} + 10\hat{j} + 20\hat{k})\text{ N}$ . The instantaneous power supplied to the particle is:

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Answer: (d)

$P = \vec{F} \cdot \vec{v}$ .
$P = (10)(5) + (10)(-3) + (20)(6) = 50 - 30 + 120 = 140\text{ W}$
So the answer is (d) $140\text{ W}$ .

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