A particle moving with kinetic energy E has de Broglie wavelength λ. If energy Δ E is added to its energy, the wavelength become λ /2. Value of Δ E, is: (a) E (b) 3E (c) 2E (d) 4E

Answer: (b). λ ∝ 1/√(E), so halving λ needs E' = 4E. Δ E = 4E - E = 3E. So the answer is (b) 3E.

A particle moving with kinetic energy E has de Broglie wavelength λ… | JEE Main 2020 (9 Jan, Shift 1)

Q111JEE Main 2020 · 9 JAN · SHIFT 1Easy

Matter Waves: de Broglie Wavelength

A particle moving with kinetic energy E has de Broglie wavelength $\lambda$ . If energy $\Delta$ E is added to its energy, the wavelength become $\lambda$ /2. Value of $\Delta$ E, is:

Show answer and solution

Answer: (b)

$\lambda \propto \dfrac{1}{\sqrt{E}}$ , so halving $\lambda$ needs $E' = 4E$ .
$\Delta E = 4E - E = 3E$ .
So the answer is (b) 3E.

Report a mistake

More questions on Matter Waves: de Broglie Wavelength

An electron is accelerated from rest through a potential difference of V volt. If the…NEET 2020 (Phase 1)
An electron, a doubly ionized helium ion (He++) and a proton are having the same kinetic…JEE Main 2020 (6 Sep, Shift 1)
A particle is moving 5 times as fast as an electron. The ratio of the de-Broglie…JEE Main 2020 (2 Sep, Shift 2)
Assuming the nitrogen molecule is moving with r.m.s. velocity at 400 K, the de-Broglie…JEE Main 2020 (6 Sep, Shift 2)
An electron (of mass m) and a photon have the same energy E in the range of a few eV. The…JEE Main 2020 (7 Jan, Shift 2)
An electron (mass m) with initial velocity v = v₀i + v₀j is in an electric field E =…JEE Main 2020 (8 Jan, Shift 2)
An electron of mass m and magnitude of charge |e| initially at rest gets accelerated by a…JEE Main 2020 (9 Jan, Shift 2)
Particle A of mass mA = m/2 moving along the x-axis with velocity v0 collides elastically…JEE Main 2020 (4 Sep, Shift 1)

Matter Waves: de Broglie Wavelength question from JEE Main 2020 (9 Jan, Shift 1)

More questions on Matter Waves: de Broglie Wavelength