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JEE Main 2003 (AIEEE) · Moving Charge in a Magnetic Field

Moving Charge in a Magnetic Field question from JEE Main 2003 (AIEEE)

Q122JEE Main 2003 · AIEEEEasy

Moving Charge in a Magnetic Field

A particle of charge −16×10−18-16 \times 10^{-18} coulomb moving with velocity 10ms−110ms^{-1} along the xx-axis enters a region where a magnetic field of induction BB is along the yy-axis, and an electric field of magnitude 104V/m10^{4}V/m is along the negative zz-axis. If the charged particle continues moving along the xx-axis, the magnitude of BB is

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Answer: (a)

  1. Moving undeflected along x ⇒∣q∣E=∣q∣vB\Rightarrow |q|E = |q|vB (the sign of qq cancels)
  2. B=Ev=10410=103 Wb/m2B = \dfrac{E}{v} = \dfrac{10^{4}}{10} = 10^{3}\text{ Wb/m}^2
  3. So the answer is (a) 103 Wb/m210^{3}\text{ Wb/m}^2.
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