A particle of charge ' q ' and mass ' m ' moves in a circular orbit of radius ' r ' with angular speed ' ω '. The ratio of the magnitude of its magnetic moment to that of its angular momentum depends upon (a) q and m (b) ω and m (c) ω and q (d) ω, q and m

Answer: (a). I = (qω)/(2π), μ = Iπ r² = (qω r²)/(2) L = mω r² μ/L = q/2m: depends on q and m only, so the answer is (a).

A particle of charge ' q ' and mass ' m ' moves in a circular orbit… | MHT CET 2026 (18 Apr, Shift 2)

Q2MHT CET 2026 · 18 APR · SHIFT 2Easy

Current Loop as a Magnetic Dipole

A particle of charge ' $q$ ' and mass ' $m$ ' moves in a circular orbit of radius ' $r$ ' with angular speed ' $\omega$ '. The ratio of the magnitude of its magnetic moment to that of its angular momentum depends upon

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Answer: (a)

$I = \frac{q\omega}{2\pi}$ , $\mu = I\pi r^2 = \frac{q\omega r^2}{2}$
$L = m\omega r^2$
$\frac{\mu}{L} = \frac{q}{2m}$ : depends on $q$ and $m$ only, so the answer is (a).

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Current Loop as a Magnetic Dipole question from MHT CET 2026 (18 Apr, Shift 2)

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