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JEE Main 2005 (AIEEE) · Gravitational Potential & Energy

Gravitational Potential & Energy question from JEE Main 2005 (AIEEE)

Q36JEE Main 2005 · AIEEEEasy

Gravitational Potential & Energy

A particle of mass 10 g10\text{ g} is kept on the surface of a uniform sphere of mass 100 kg100\text{ kg} and radius 10 cm.10\text{ cm}. Find the work to be done against the gravitational force between them to take the particle far away from the sphere (you may take G=6.67×10−11 N m2/kg2G = 6.67 \times 10^{-11}\text{ N m}^2/\text{kg}^2)

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Answer: (c)

  1. Work to take the particle to infinity =U∞−UR=GMmR= U_\infty - U_R = \frac{GMm}{R}
  2. W=6.67×10−11×100×0.010.1W = \frac{6.67\times10^{-11}\times 100 \times 0.01}{0.1}
  3. W=6.67×10−10 JW = 6.67\times10^{-10}\ \text{J}
  4. So the answer is (c).
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