A particle of mass 100 g is thrown vertically upwards with a speed of 5 m/s. The work done by the force of gravity during the time the particle goes up is (a) -0.5 J (b) -1.25 J (c) 1.25 J (d) 0.5 J

Answer: (b). Work-energy theorem: Wg = Δ K = 0 - 1/2mu² (speed becomes zero at the top). Wg = -1/2(0.1)(5)² = -1.25 J So the answer is (b) -1.25 J.

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Work by a Constant Force

A particle of mass $100\text{ g}$ is thrown vertically upwards with a speed of $5\text{ m/s}$ . The work done by the force of gravity during the time the particle goes up is

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Answer: (b)

Work-energy theorem: $W_g = \Delta K = 0 - \frac{1}{2}mu^2$ (speed becomes zero at the top).
$W_g = -\frac{1}{2}(0.1)(5)^2 = -1.25$ J
So the answer is (b) $-1.25$ J.

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