A particle of mass 5 g is executing S.H.M. with an amplitude 0.3 m and time period π/5 s. The maximum value of the force acting on the particle is (a) 0.15 N (b) 4 N (c) 5 N (d) 0.3 N

Answer: (a). ω = 2π/T = (2π)/(π/5) = 10 rad/s Fmax = mAω² = 0.005× 0.3× 100 Fmax = 0.15 N So the answer is (a) 0.15 N.

A particle of mass 5 g is executing S.H.M. with an amplitude 0.3 m… | MHT CET 2021 (20 Sep, Shift 1)

Q55MHT CET 2021 · 20 SEP · SHIFT 1Easy

Velocity & Acceleration in SHM

A particle of mass 5 g is executing S.H.M. with an amplitude 0.3 m and time period $\frac{\pi}{5}$ s. The maximum value of the force acting on the particle is

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Answer: (a)

$\omega = \frac{2\pi}{T} = \frac{2\pi}{\pi/5} = 10$ rad/s
$F_{max} = mA\omega^2 = 0.005\times 0.3\times 100$
$F_{max} = 0.15$ N
So the answer is (a) 0.15 N.

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