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NEET 1991 (AIPMT) · Angular Momentum & its Conservation

Angular Momentum & its Conservation question from NEET 1991 (AIPMT)

Q98NEET 1991 · AIPMTMedium

Angular Momentum & its Conservation

A particle of mass $m = 5$ is moving with a uniform speed $v = 3\sqrt{2}$ in the $XOY$ plane along the line $Y = X + 4$ . The magnitude of the angular momentum of the particle about the origin is

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Answer: (a)

$L = mv\,d$ , where $d$ is the perpendicular distance of the line of motion from the origin.
Line $x-y+4=0$ : $d=\frac{4}{\sqrt{1^2+1^2}}=2\sqrt2$
$L=5\times3\sqrt2\times2\sqrt2=60$
So the answer is (a) 60 units.

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