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JEE Main 2019 (11 Jan, Shift 2) · Moving Charge in a Magnetic Field

Moving Charge in a Magnetic Field question from JEE Main 2019 (11 Jan, Shift 2)

Q90JEE Main 2019 · 11 JAN · SHIFT 2Medium

Moving Charge in a Magnetic Field

A particle of mass m and charge q is in an electric and magnetic field given by

$\vec{E} = 2\hat{i} + 3\hat{j};\ \vec{B} = 4\hat{j} + 6\hat{k}.$

The charged particle is shifted from the origin to the point P(x = 1; y = 1) along a straight path. The magnitude of the total work done is:

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Answer: (d)

The magnetic force is always perpendicular to velocity, so it does no work.
Work is done only by $\vec{E}$ : $W = q\vec{E} \cdot \vec{d}$ with $\vec{d} = \hat{i} + \hat{j}$ .
$W = q(2 \times 1 + 3 \times 1) = 5q$
So the answer is (d) $5q$ .

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