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NEET 2021 · Escape Velocity

Escape Velocity question from NEET 2021

Q48NEET 2021Medium

Escape Velocity

A particle of mass 'm' is projected with a velocity vv = kVe = (k < 1) from the surface of the earth. (Ve = escape velocity)

The maximum height above the surface reached by the particle is:

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Answer: (a)

  1. Energy conservation: 12mk22GMR=GMm(1R−1R+h)\frac{1}{2}mk^2\frac{2GM}{R} = GMm\left(\frac{1}{R} - \frac{1}{R+h}\right).
  2. 1R+h=1−k2R⇒R+h=R1−k2\frac{1}{R+h} = \frac{1-k^2}{R} \Rightarrow R+h = \frac{R}{1-k^2}.
  3. h=Rk21−k2h = \frac{Rk^2}{1-k^2}.
  4. So the answer is (a) Rk21−k2\frac{Rk^{2}}{1-k^{2}}.
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