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MHT CET 2023 (10 May, Shift 1) · Angular Momentum & its Conservation

Angular Momentum & its Conservation question from MHT CET 2023 (10 May, Shift 1)

Q36MHT CET 2023 · 10 MAY · SHIFT 1Medium

Angular Momentum & its Conservation

A particle of mass ' $\mathrm{m}$ ' is rotating along a circular path of radius ' $r$ ' having angular momentum ' $L$ '. The centripetal force acting on the particle is given by

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Answer: (d)

$L = mvr \Rightarrow v = \dfrac{L}{mr}$
$F = \dfrac{mv^2}{r} = \dfrac{m}{r}\cdot\dfrac{L^2}{m^2r^2} = \dfrac{L^2}{mr^3}$
So the answer is (d).

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