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MHT CET 2023 (9 May, Shift 2) · Non-Uniform Circular Motion

Non-Uniform Circular Motion question from MHT CET 2023 (9 May, Shift 2)

Q13MHT CET 2023 · 9 MAY · SHIFT 2Medium

Non-Uniform Circular Motion

A particle of mass ' $m$ ' moves along a circle of radius ' $r$ ' with constant tangential acceleration. If K.E. of the particle is ' $E$ ' by the end of third revolution after beginning of the motion, then magnitude of tangential acceleration is

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Answer: (b)

Work done by tangential force = gain in KE: $E = m a_t s$
Distance in 3 revolutions: $s = 3(2\pi r) = 6\pi r$
$a_t = \frac{E}{6\pi r m}$
So the answer is (b).

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