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MHT CET 2024 (10 May, Shift 2) · Centripetal Acceleration & Force

Centripetal Acceleration & Force question from MHT CET 2024 (10 May, Shift 2)

Q16MHT CET 2024 · 10 MAY · SHIFT 2Medium

Centripetal Acceleration & Force

A particle of mass ' mm ' performs uniform circular motion of radius ' rr ' with linear speed ' vv ' under the application of force ' FF '. If ' mm ', ' vv ' and rr ' are all increased by 20%20\% the necessary change in force required to maintain the particle in uniform circular motion, is

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Answer: (b)

  1. F=mv2rF = \frac{mv^2}{r}
  2. F′=(1.2m)(1.2v)21.2r=1.44 FF' = \frac{(1.2m)(1.2v)^2}{1.2r} = 1.44\,F
  3. Increase =44%= 44\%
  4. So the answer is (b) 44%44\%.
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