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MHT CET 2021 (23 Sep, Shift 1) · Energy in SHM

Energy in SHM question from MHT CET 2021 (23 Sep, Shift 1)

Q53MHT CET 2021 · 23 SEP · SHIFT 1Easy

Energy in SHM

A particle performing S.H.M. when displacement is ' $x$ ', the potential energy and restoring force acting on it are denoted by ' $E$ ' and ' $F$ ' respectively. The relation between $x, E$ and $F$ is

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Answer: (c)

$E = \dfrac{1}{2}kx^2$ and $F = -kx$ .
$\dfrac{2E}{F} = \dfrac{kx^2}{-kx} = -x$
$\dfrac{2E}{F} + x = 0$
So the answer is (c).

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