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MHT CET 2024 (10 May, Shift 1) · Velocity & Acceleration in SHM

Velocity & Acceleration in SHM question from MHT CET 2024 (10 May, Shift 1)

Q24MHT CET 2024 · 10 MAY · SHIFT 1Easy

Velocity & Acceleration in SHM

A particle performing S.H.M. with maximum velocity ' $V$ '. If the amplitude double and periodic time is made, $\left(\frac{1}{3}\right)$ rd then the maximum velocity is

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Answer: (a)

$v_{max} = A\omega = \frac{2\pi A}{T}$ , so $v_{max} \propto \frac{A}{T}$
$A' = 2A$ , $T' = \frac{T}{3}$ : $v' = \frac{2}{1/3}V = 6V$
So the answer is (a) $6V$ .

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