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MHT CET 2026 (15 Apr, Shift 1) · Angular Variables

Angular Variables question from MHT CET 2026 (15 Apr, Shift 1)

Q10MHT CET 2026 · 15 APR · SHIFT 1Easy

Angular Variables

A particle performing U.C.M. of radius π2\frac{\pi}{2} m makes 'x' revolutions in time t. Its tangential velocity is

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Answer: (b)

  1. ω=2πxt\omega = \frac{2\pi x}{t} for xx revolutions in time tt.
  2. v=rω=π2⋅2πxt=π2xtv = r\omega = \frac{\pi}{2} \cdot \frac{2\pi x}{t} = \frac{\pi^2 x}{t}.
  3. So the answer is (b) π2xt\frac{\pi^2 x}{t}.
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