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MHT CET 2025 (19 Apr, Shift 2) · Angular Variables

Angular Variables question from MHT CET 2025 (19 Apr, Shift 2)

Q14MHT CET 2025 · 19 APR · SHIFT 2Easy

Angular Variables

A particle performing uniform circular motion of radius π2 m\frac{\pi}{2}\text{ m} makes xx revolutions in time tt. Its tangential velocity is

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Answer: (c)

  1. ω=2πxt\omega = \frac{2\pi x}{t} for xx revolutions in time tt.
  2. v=rω=π2⋅2πxt=π2xtv = r\omega = \frac{\pi}{2} \cdot \frac{2\pi x}{t} = \frac{\pi^2 x}{t}.
  3. So the answer is (c) π2xt\frac{\pi^2 x}{t}.
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