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MHT CET 2021 (21 Sep, Shift 2) · Rotational Kinetic Energy, Work & Power

Rotational Kinetic Energy, Work & Power question from MHT CET 2021 (21 Sep, Shift 2)

Q37MHT CET 2021 · 21 SEP · SHIFT 2Medium

Rotational Kinetic Energy, Work & Power

A particle performs rotational motion with an angular momentum 'L'. If frequency of rotation is doubled and its kinetic energy becomes one fourth, the angular momentum becomes.

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Answer: (c)

$L = \frac{2K}{\omega}$
$\omega' = 2\omega$ , $K' = \frac{K}{4}$ : $L' = \frac{2(K/4)}{2\omega} = \frac{L}{8}$
So the answer is (c) $\frac{L}{8}$ .

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