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MHT CET 2025 (23 Apr, Shift 1) · Progressive Wave Equation

Progressive Wave Equation question from MHT CET 2025 (23 Apr, Shift 1)

Q28MHT CET 2025 · 23 APR · SHIFT 1Easy

Progressive Wave Equation

A particle performs S.H.M. of amplitude 'A' and wavelength ' λ\lambda ', Then the velocity of the wave (V) and the maximum particle velocity (v) are related as

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Answer: (c)

  1. Maximum particle velocity v=Aωv = A\omega; wave velocity V=ωk=ωλ2πV = \frac{\omega}{k} = \frac{\omega\lambda}{2\pi}.
  2. vV=Aωωλ/2π=2πAλ\frac{v}{V} = \frac{A\omega}{\omega\lambda/2\pi} = \frac{2\pi A}{\lambda}
  3. So the answer is (c) v=2πAλVv = \frac{2\pi A}{\lambda}V.
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