A particle starts from the origin at t = 0 with an initial velocity of 3.0 i m/s and moves in the x-y plane with a constant acceleration (6i + 4j) m/s2. The x-coordinate of the particle at the instant when its y-coordinate is 32 m is D meters. The value of D is:- (a) 40 (b) 32 (c) 50 (d) 60

Answer: (d). y = 12(4)t² = 2t² = 32 ⇒ t = 4 s x = 3t + 12(6)t² = 12 + 48 = 60 m So the answer is (d) D = 60.

A particle starts from the origin at t = 0 with an initial velocity… | JEE Main 2020 (9 Jan, Shift 2)

Q11JEE Main 2020 · 9 JAN · SHIFT 2Medium

Motion in a Plane (2-D Kinematics)

A particle starts from the origin at t = 0 with an

initial velocity of 3.0 $\hat{i}$ m/s and moves in the

x-y plane with a constant acceleration $\left(6\hat{i} + 4\hat{j}\right)$ m/s2. The x-coordinate of the particle at the instant when its y-coordinate is 32 m is D meters. The value of D is :-

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Answer: (d)

$y = \frac12(4)t^2 = 2t^2 = 32 \Rightarrow t = 4$ s
$x = 3t + \frac12(6)t^2 = 12 + 48 = 60$ m
So the answer is (d) $D = 60$ .

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Motion in a Plane (2-D Kinematics) question from JEE Main 2020 (9 Jan, Shift 2)

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